What is the vertex of #y=2(x-3)^2+4#?

Answer 1

#(3,4)#

This is written in vertex form, a convenient method for writing quadratic equations in which the vertices can be found algebraically and are obvious from the equation itself.

The vertex form is

#y=a(x-h)^2+k#
When #(h,k)# is the vertex of the parabola.
The only tricky thing to watch out for is the #x#-coordinate. In vertex form, it's written as #-h#, so the actual #x#-coordinate #h# will be the opposite of whatever is written inside the square term.

Thus,

#h=3# #k=4#
The vertex is at #(3,4)#.

graph{[-8.02, 14.48, -1.53, 9.72]} = 2(x-3)^2+4

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Answer 2

The vertex of the parabola described by the equation y = 2(x - 3)^2 + 4 is (3, 4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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