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What is the vertex of # y = (1/8)(x – 5)^2 - 3#?

Answer 1

The vertex is #v(1/20, 201/3200)#

#f(x) = y=1/8(x–5)^2−3# #f(x) = 1/8 (x^2 - 10x + 1) # Now for any #f(x) = y = ax^2 + bx + c " "# form of the equation The vertex, #v(h, k)# # h = -b/(2a); and k = f(h)# # h = 1/20; k = f(1/20) = 201/3200 ~~ .063# The vertex is #v(1/20, 201/3200)#

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Answer 2

Avery Alexander

The vertex of the parabola represented by the equation (y = \frac{1}{8}(x - 5)^2 - 3) is ((5, -3)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.