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What is the vertex of the parabola #y=(x+5)^2+49#?

Answer 1

Genesis Allen

(-5 , 49)

The vertex form of the parabola is #y =a(x-h)^2 + k #

where the vertex's coordinates are (h, k).

The function # y = (x + 5)^2+ 49" is in this form "#

and in contrast, k = 49 and h = - 5

Vertex, then, is equal to (-5, 49) graph{(x+5)^2+49 [-320, 320, -160, 160]}.

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Answer 2

Jameson Allen

The vertex of the parabola y=(x+5)^2+49 is (-5, 49).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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