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What is the vertex of the parabola #y=3(x-4)^2-22#?

Answer 1

Genesis Allen

#(4, -22)#

The formula

#y = 3(x-4)^2-22#

is situated in the vertex form:

#y = a(x-h)+k#

with multiplier #a = 3# and vertex #(h, k) = (4, -22)#

One of the nice things about vertex form is that its vertex coordinates can be read right away.

Notice that #(x-4)^2 >= 0#, taking its minimum value #0# when #x=4#. When #x=4# we have #y = 3(4-4)^2-22 = 0-22 = -22#.

So the vertex is at #(4, -22)#.

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Answer 2

Isaiah Anthony

The vertex of the parabola is (4, -22).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.