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What is the vertex form of #y=x^2+7x-3#?

Answer 1

#y= (x+7/2)^2 - 61/4# or #4y = (2x+7)^2 -61 #

For a quadratic of the form #y=ax^2 +bx +c# the vertex form is #y = a[(x+b/(2a))^2 -(b/(2a))^2] +c# In this case that gives us #y = (x+7/2)^2 - 49/4 - 3# #y= (x+7/2)^2 - 61/4#

The vertex is then #(-7/2, -61/4)#

Multiplying throughout by #4# gives #4y = (2x+7)^2 -61 #

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Answer 2

Avery Alexander

The vertex form of the quadratic equation y = x^2 + 7x - 3 is y = (x + 7/2)^2 - 59/4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.