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What is the vertex form of #y=x^2-4x+3#?

Answer 1

#y = (x-2)^2 -1#

Use completing the square to get the equation into the form #y=a(x+b)^2 +c# In this case #a = 1# and #b = (-4)/2 = -2# #c = -b^2 +3 = -4 +3 = -1# #y = (x-2)^2 -1#

The vertex is #(2, -1)#

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Answer 2

Eva Adamson

The vertex form of the quadratic equation ( y = x^2 - 4x + 3 ) is ( y = (x - 2)^2 - 1 ).

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Answer 3

Genesis Allen

The vertex form of the quadratic function ( y = x^2 - 4x + 3 ) is ( y = a(x - h)^2 + k ), where ( (h, k) ) represents the coordinates of the vertex.

To find the vertex form, we complete the square on the expression ( x^2 - 4x ):

[ y = x^2 - 4x + 3 ] [ = (x^2 - 4x + 4) - 4 + 3 ] [ = (x - 2)^2 - 1 ]

So, the vertex form of ( y = x^2 - 4x + 3 ) is ( y = (x - 2)^2 - 1 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.