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What is the vertex form of #y=4x^2 + 8x − 19 #?

Answer 1

Isaiah Anthony

#(-1,-23)#

The vertex equation is: #x_v=(-b)/(2a)#

for these function, #x_v=(-8)/(2*4)=-1#

now we substitute #x# by #-1# in the function equation, #f(-1)=4·(-1)^2+8·(-1)-19=-23#

so the vertex is point #(-1,-23)#.

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Answer 2

Avery Alexander

The vertex form of the quadratic function ( y = 4x^2 + 8x - 19 ) is ( y = 4(x + 1)^2 - 23 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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