# What is the vertex form of #y= 2x^2+7x-15#?

#y=2(x+7/4)^2+169/8#

Given -

#y=2x^2+7x-15#

Find the vertex

#x=(-b)/(2a)= (-7)/(2 xx 2)=-7/4#

#y=2(-7/4)^2+7(-7/4)-15#

#y=2(49/16)-49/4-15#

#y=49/8-49/4-15=169/8#

Quadratic equation in vertex form

#y=a(x-h)^2+k#

Where -

#a# is the co-efficient of#x^2#

#h# is#x # coordinate of the vertex

#k# is the#y# coordinate of the vertex

#y=2(x-(-7/4))^2+169/8#

#y=2(x+7/4)^2+169/8#

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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