# What is the vertex and #y#-intercept of #f(x) = -4(x+3)^2+7#?

(0,-29) is the y intercept

(-3,55) is the vertex, a maximum

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The vertex of the function ( f(x) = -4(x+3)^2+7 ) is (-3, 7), and the y-intercept is (0, -5).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you find the focus, directrix and sketch #y=1/3x^2-x#?
- What is the vertex and #y#-intercept of #f(x) = -4(x+3)^2+7#?
- Prove that if #a,b# and #c# are in A.P., #b^2-ac>0#, if they are in G.P. then #b^2-ac=0# and if they are in H.P. then #b^2-ac<0#?
- How do I find the vertex of #y=(x+2)^2-3#?
- How do you find the vertex, directrix and focus of #y= -3(x+1)^2 - 4#?

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