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What is the vertex and focus of the parabola described by #x^2-4x+y+3=0#?

Answer 1

#x^2-4x+y+3=0# #" "# #y=-x^2+4x-3# #" "# #y=-(x^2-4x+3)# #" "# #y=-(x^2-4x+3+1-1)# #" "# #y=-(x^2-4x+4-1)# #" "# #y=-(x^2-4x+4)+1# #" "# #y=-(x-2)^2+1# #" "# The vertex of the parabola is #(2,1)# #" "# The focus of thus parabola is #-1/4#

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Answer 2

Eva Abramson

The vertex of the parabola is at (2, -3) and the focus is at (2, -2.75).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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