What is the value of #x# in a triangle with angles #70, 60#, and #8x + 2#?

Answer 1

#x=6#

Since any triangle has a sum of interior angles of #180^@#, we can set up an equation to solve for #x#:
#70+60+(8x+2)=180# #60+(8x+2)=110# #8x+2=50# #8x=48# #x=6#
#:.#, the value of #x# is #6#.
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Answer 2

To find the value of ( x ) in a triangle with angles 70, 60, and ( 8x + 2 ), we use the fact that the sum of angles in a triangle is always 180 degrees.

So, we have:

[ 70 + 60 + (8x + 2) = 180 ]

[ 130 + 8x + 2 = 180 ]

[ 8x + 132 = 180 ]

[ 8x = 180 - 132 ]

[ 8x = 48 ]

[ x = \frac{48}{8} ]

[ x = 6 ]

Therefore, the value of ( x ) in the given triangle is 6.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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