What is the value of #x# in a triangle with angles #70, 60#, and #8x + 2#?
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To find the value of ( x ) in a triangle with angles 70, 60, and ( 8x + 2 ), we use the fact that the sum of angles in a triangle is always 180 degrees.
So, we have:
[ 70 + 60 + (8x + 2) = 180 ]
[ 130 + 8x + 2 = 180 ]
[ 8x + 132 = 180 ]
[ 8x = 180 - 132 ]
[ 8x = 48 ]
[ x = \frac{48}{8} ]
[ x = 6 ]
Therefore, the value of ( x ) in the given triangle is 6.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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