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What is the value of the hypotenuse of an isosceles triangle with a perimeter equal to #16 + 16sqrt2#?

Answer 1

Sophia Alfred

That triangle is half a square. #(t, t, t sqrt 2)#

#2p = t + t + t sqrt2 = 16 + 16sqrt 2#

#t = 16 cdot (1 + sqrt 2)/(2 + sqrt 2)# // times #sqrt 2#

Hypotenuse = #t sqrt 2 = 16 cdot (sqrt 2 + 2)/(2 + sqrt 2)#

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Answer 2

Theodore Abad

The value of the hypotenuse of an isosceles triangle with a perimeter equal to (16 + 16\sqrt{2}) is (8 + 8\sqrt{2}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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