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What is the value of the expression #x^3y^2+x^2y^3-(x+y)# when x=4 and y=-3?

Answer 1

Genesis Allen

143

You would change x and y to the specified values;

#4^3(-3)^2+4^2(-3)^3-(4-3)#

#=64*9+16(-27)-1=576-432-1=143#

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Answer 2

Isaiah Anthony

To find the value of the expression (x^3y^2+x^2y^3-(x+y)) when (x=4) and (y=-3), substitute (x) and (y) into the expression and calculate the result:

(x^3y^2+x^2y^3-(x+y))

(= (4)^3(-3)^2 + (4)^2(-3)^3 - (4 + (-3)))

(= 64(9) + 16(-27) - (1))

(= 576 - 432 - 1)

(= 576 - 433)

(= 143)

Therefore, the value of the expression when (x=4) and (y=-3) is (143).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.