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What is the total number of moles present in a 52.0 gram sample of #NaN_3#?

Gram-formula mass = 65.0 grams/mole

Answer 1

Ellie Andrews

#"0.800 moles"#

Given a compound and a mass, the following formula can be used to calculate moles:

#n = m/M#

#n# = moles #m# = mass in grams #("g")# #M# = molar mass #("g/mol")#

The total of the atomic masses in the compound is the molar mass.

#"Na" = "22.99 g/mol"# #"N" = "14.01 g/mol" xx 3 -># (there are #3# #"N"# atoms)

Add them up and you get #"65.02 g/mol"#

#n = m/M#

# = (52.0 cancel("g"))/(65.02 cancel("g")/"mol")#

#= "0.799753921 moles"#

#= "0.800 moles " -># (rounded to three sig figs)

Therefore, there are #0.800# moles in 52.0g of #"NaN"_3#.

I hope that was clear.

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Answer 2

Caleb Adams

Divide the given mass by the molar mass of NaN3, which is approximately 65.01 g/mol, to determine the total number of moles present in a 52.0 gram sample of NaN3. The total number of moles present in the sample is approximately 0.799 moles.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.