What is the total masses of the reactants for the equation: #2SeO_2 (g) + O_2->2SeO_3 (g)#?

Answer 1

#2SeO_2(g) + O_2(g) rarr 2SeO_3(g)#

The equivalent mass of #SeO_2# is #126.96# #g*mol^-1#. Dioxygen gas has an equivalent mass of #32.00# #g*mol^-1#. So the reactant mass is #126.96*gxx2+32.00*g# #=# #??g#.

What mass of #SeO_3(g)# results?

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Answer 2

Natalie Anton

To find the total mass of the reactants, you need to determine the molar masses of each reactant and then multiply them by their respective coefficients in the balanced chemical equation.

Molar mass of SeO2 = 78.96 g/mol Molar mass of O2 = 32.00 g/mol

Total mass of reactants = (2 * molar mass of SeO2) + (1 * molar mass of O2)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What is the total masses of the reactants for the equation: #2SeO_2 (g) + O_2-&gt;2SeO_3 (g)#?

What is the total masses of the reactants for the equation: #2SeO_2 (g) + O_2->2SeO_3 (g)#?