# What is the theoretical mass of water produced from ten moles of #NaHCO_3#?

The theoretical mass of water that can be produced by the decomposition of ten moles of sodium bicarbonate is

Balanced equation

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The theoretical mass of water produced from ten moles of NaHCO₃ can be calculated using stoichiometry. The balanced chemical equation for the reaction of NaHCO₃ producing water is:

2 NaHCO₃ -> Na₂CO₃ + CO₂ + H₂O

From the equation, it's clear that 2 moles of NaHCO₃ produce 1 mole of water. Therefore, 10 moles of NaHCO₃ will produce 5 moles of water.

The molar mass of water (H₂O) is approximately 18.015 g/mol.

So, the theoretical mass of water produced from 10 moles of NaHCO₃ is:

5 moles * 18.015 g/mol ≈ 90.075 g

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