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What is the the vertex of #y = (x -3)^2+8x-15 #?

Answer 1

Nathan Axel

The vertex is #(-1,-7)#.

First expand and collect like terms:

#y=x^2-6x+9+8x-15 # #y=x^2 + 2x -6#

Now the vertex is #(h,k)#, where #h=-b/(2a)# and #k# is the value of #y# when #h# is substituted into the function.

#h=-2/(2*1)=-1#

#k = (-1)^2 +2(-1) -6 = 1-2-6=-7#

The vertex is #(-1,-7)#.

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Answer 2

Eva Adamson

The vertex of the function y = (x - 3)^2 + 8x - 15 is (3, -6).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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