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What is the the vertex of #y =3x^2+5x+8 #?

Answer 1

Vertex (-5/6, 213/36

x-coordinate of vertex: #x = -b/(2a) = - 5/6# y-coordinate of vertex: #y (-5/6) = 3(25/36) - 5(5/6) + 8 = 75/36 - 25/6 + 8 =# #= 75/36 - 150/36 + 288/36 = 213/36#

Vertex (-5/6, 213/36)

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Answer 2

Eva Abramson

The vertex of the quadratic function y = 3x^2 + 5x + 8 is calculated using the formula:

x = -b / (2a), where a = 3 and b = 5 in this equation.

Substituting the values:

x = -5 / (2 * 3) = -5 / 6

To find the corresponding y-coordinate, plug this value of x into the original equation:

y = 3(-5/6)^2 + 5(-5/6) + 8

y ≈ 6.917

So, the vertex of the parabola is approximately (-5/6, 6.917).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.