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What is the the vertex of #y=2x^2+15x -2 #?

Answer 1

Julia Adams

#x_("vertex")=-3.75#

I will let you work out #y_("vertex")#

Given:#" "y=2x^2+15x-2#

A quick way of finding #x_("vertex")# is as follows:

Write as #" "y=2(x^2+15/2x)-2#

Now apply :#" "(-1/2)xx15/2 = -15/4 = 3.75#

#color(blue)(x_"vertex"=-3.75)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Now substitute back into the original equation to find #y_("vertex")#

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Answer 2

Eva Adamson

The vertex of the quadratic function y = 2x^2 + 15x - 2 is (-3.75, -21.875).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.