What is the the vertex of #y = -12x^2 - 4x-5#?
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The vertex of the quadratic function y = -12x^2 - 4x - 5 is at the point (-1/6, -79/3).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you find the vertex and axis of symmetry of #y=x^2+8x-7#?
- How do you solve the equation by completing the square: #x^2 + 2x - 8 = 0#?
- How do you find the vertex for #y = 2x^2 + 8x -3#?

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