What is the surface area of the solid created by revolving #f(x) = e^(x-2) , x in [2,7]# around the x axis?
Paisley JohnsonSee the answer below:
By signing up, you agree to our Terms of Service and Privacy Policy
Scarlett AllisonThe surface area of the solid created by revolving ( f(x) = e^{x-2} ) over the interval ([2,7]) around the x-axis is approximately 90.446 square units.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the surface area of the solid created by revolving #f(x)=e^(x^2-x)/(x+1)-e^x# over #x in [0,1]# around the x-axis?
- What is a solution to the differential equation #dy/dx=(x+sinx)/(3y^2)#?
- How do you find the circumference of the ellipse #x^2+4y^2=1#?
- What is the volume of the solid produced by revolving #f(x)=x^2+3x-sqrtx, x in [0,3] #around the x-axis?
- How do you Find the exponential growth rate for a given data set?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7