What is the surface area of the solid created by revolving #f(x) =e^(3x-2) , x in [1,2]# around the x axis?
Luke AlvarezSee the answer below:
By signing up, you agree to our Terms of Service and Privacy Policy
Christopher AllersTo find the surface area of the solid created by revolving f(x) = e^(3x-2) around the x-axis on the interval [1,2], you can use the formula for the surface area of revolution:
S = ∫[a,b] 2πf(x)√(1 + (f'(x))^2) dx
First, find f'(x), then use it to compute √(1 + (f'(x))^2). Finally, integrate the expression 2πf(x)√(1 + (f'(x))^2) over the interval [1,2].
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you find the differential #dy# of the function #y=sqrtx+1/sqrtx#?
- How do you find the volume of #y=2x^2#; #y=0#; #x=2# revolved about the x axis?
- If #y=arcsin(4x^2)#, then what is #dy/dx#?
- What is the solution of the Differential Equation # x(dy/dx)+3y+2x^2=x^3+4x #?
- What is a solution to the differential equation #dy/dx=(x+1)/x#?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7