What is the sum of the measures of the interior angles of a pentagon?

Answer 1

Sum of the interior angles of a pentagon #=540^@#

The general formula for the sum of the interior angles of an n-gon (with #n>= 3#) is
#color(white)("XXX")180^@xx(n-2)#

A pentagon has #5# sides (i.e. #n=5#)

The diagram below may help to understand why this formula works:

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Answer 2

The sum of the measures of the interior angles of any polygon can be found using the formula:

[ \text{Sum of interior angles} = (n - 2) \times 180^\circ ]

Where ( n ) is the number of sides of the polygon.

For a pentagon, ( n = 5 ), so:

[ \text{Sum of interior angles} = (5 - 2) \times 180^\circ = 3 \times 180^\circ = 540^\circ ]

Therefore, the sum of the measures of the interior angles of a pentagon is ( 540^\circ ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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