What is the sum of the measures of the interior angles of a pentagon?
Sum of the interior angles of a pentagon
The general formula for the sum of the interior angles of an n-gon (with A pentagon has The diagram below may help to understand why this formula works:
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The sum of the measures of the interior angles of any polygon can be found using the formula:
[ \text{Sum of interior angles} = (n - 2) \times 180^\circ ]
Where ( n ) is the number of sides of the polygon.
For a pentagon, ( n = 5 ), so:
[ \text{Sum of interior angles} = (5 - 2) \times 180^\circ = 3 \times 180^\circ = 540^\circ ]
Therefore, the sum of the measures of the interior angles of a pentagon is ( 540^\circ ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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