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What is the sum of the interior angles of a hendecagon?

Answer 1

Sum of interior angles of a hendecagon #=1620^@#

The real issue here is knowing that a "hendecagon" is an #11# sided (and angled) polygon.

The formula for the sum of the interior angles of an #n#-gon is #color(white)("XXX")180^@xx(n-2)color(white)("XXXXX")#provided #n>=3#

An #11#-gon (hendecagon) can be divided into #9# triangles by connecting vertices; each triangle has an interior angle sum of #180^@#

Sum of interior angles of hendecagon #=180^@ xx 9 = 1620^@#

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Answer 2

Maverick Smith

The sum of the interior angles of any polygon can be found using the formula:

[ S = (n - 2) \times 180^\circ ]

where ( S ) is the sum of the interior angles and ( n ) is the number of sides of the polygon.

For a hendecagon, which has ( n = 11 ) sides, the sum of the interior angles would be:

[ S = (11 - 2) \times 180^\circ = 9 \times 180^\circ = 1620^\circ ]

Therefore, the sum of the interior angles of a hendecagon is ( 1620^\circ ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.