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What is the structure of the acetal formed by reaction of ethanol with acetophenone?

Answer 1

Elias Aguila

The structure of the acetal is #"C"_6"H"_5"C"("CH"_3)("OCH"_2"CH"_3)_2#.

Ketones react in the presence of acids to form hemiacetals, and the hemiacetals can react further to form acetals.

The general equation is

#"RCOR' + 2R''OH" stackrel("HCl")(→) "RR'C"("OR''")_2 + "H"_2"O"#

The mechanism is

, #"R'" = "CH"_3#, and #"R''" = "CH"_2"CH"_3#.

So the structure of the acetal is given by the equation

#"C"_6"H"_5"COCH"_3 + "2CH"_3"CH"_2"OH" stackrel("HCl")(→) "C"_6"H"_5"C"("CH"_3)("OCH"_2"CH"_3)_2#

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Answer 2

Emilia Alvarez

The structure of the acetal formed by the reaction of ethanol with acetophenone is:

[ \text{CH}_3\text{COCH}_3 + 2\text{CH}_3\text{CH}_2\text{OH} \rightarrow \text{CH}_3\text{COCH}_2\text{CH}_3\text{OH} + \text{H}_2\text{O} ]

The acetal formed is 1-phenylethyl ethyl ether.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.