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What is the standard form of # y= (x+7)(2x+15)-(x-7)^2#?

Answer 1

#y=x^2+43x+56#

standard form is #y=ax^2+bx+c#

first multiply/distribute to expand everything: #y=(x+7)(2x+15)-(x-7)^2# #y=x(2x+15)+7(2x+15)-(x-7)(x-7)# #y=2x^2+15x+14x+105-(x(x-7)-7(x-7))# #y=2x^2+29x+105-(x^2-7x-7x+49)#

combine like terms as you go

#y=2x^2+29x+105-x^2+14x-49# #y=x^2+43x+56#

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Answer 2

Jameson Allen

The standard form of ( y = (x+7)(2x+15)-(x-7)^2 ) is ( y = 3x^2 + 44x + 124 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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