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What is the standard form of # y= (x+3)(-x-1)+(3x-7)^2#?

Answer 1

Eva Abramson

#8x^2-46x+46#

It is apparent that the highest degree of #x# in the function

#(x+3)(−x−1)+(3x−7)^2# is two. Expanding the function

#(x+3)(−x−1)+(3x−7)(3x-7)#

#(x+3)(−x)−1(x+3)+3x(3x-7)-7(3x-7)# or

#-x^2-3x-x-3+9x^2-21x-21x+49# or

#8x^2-46x+46#

As it is an function in degree #2# of form #ax^2+bx+c#

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Answer 2

Avery Alexander

The standard form of ( y = (x + 3)(-x - 1) + (3x - 7)^2 ) is ( y = -x^2 - 2x + 4 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.