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What is the standard form of #y=8(x^2 - 16) (x^2 -16)(x^3 + 8) #?

Answer 1

Isaiah Anthony

#color(crimson)(y = 8x^7 - 256x^5 + 64x^4 + 2048x^3 - 2048x^2 + 16394#

#y = 8(x^2 - 16) (x^2-16)(x^3+8)#

#y = 8 (x^4 - 32x^2 + 256)(x^3+8)#

#y = 8 (x^7 - 32x^5 + 256x^3 + 8x^4 - 256x^2 + 2048)#

#color(crimson)(y = 8x^7 - 256x^5 + 64x^4 + 2048x^3 - 2048x^2 + 16394#

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Answer 2

Abigail Allen

The standard form of the expression ( y = 8(x^2 - 16)(x^2 - 16)(x^3 + 8) ) is obtained by expanding and simplifying it. The standard form is:

[ y = 8x^7 - 256x^5 + 8x^3 - 256x^2 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.