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What is the standard form of #y-4= -(x-1)^2#?

Answer 1

#y=-x^2+2x-3#

The standard form is #y=ax^2 +bx +c# (where #a#, #b# and #c# are some numbers) So in this case, you just need to open up the parentheses of the right side of the equation and then rearrange the terms.

We have: #y-4 = -(x-1)^2# which becomes: #y-4=-(x^2-2x+1)# (note that I still keep the minus sign in front of the parenthesis)

#y-4=-x^2+2x-1#

And pass the -4 on the "other side": #y=-x^2+2x-1+4#

giving you: #y=-x^2+2x-3# which is in standard form with #a=-1#, #b=2# and #c=-3#

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Answer 2

Nathan Axel

The standard form of the given equation is ( y = -x^2 + 2x - 3 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.