What is the standard form of # y= (3x-5)(2x+12)-7x^2+15x#?

Answer 1

See a solution process below:

First, multiply the two terms in parenthesis by multiplying each individual term in the left parenthesis by each individual term in the right parenthesis.

#y = (color(red)(3x) - color(red)(5))(color(blue)(2x) + color(blue)(12)) - 7x^2 + 15x# becomes:
#y = (color(red)(3x) xx color(blue)(2x)) + (color(red)(3x) xx color(blue)(12)) - (color(red)(5) xx color(blue)(2x)) - (color(red)(5) xx color(blue)(12)) - 7x^2 + 15x#
#y = 6x^2 + 36x - 10x - 60 - 7x^2 + 15x#

We can now group and combine like terms:

#y = 6x^2 - 7x^2 + 36x - 10x + 15x - 60#
#y = (6 - 7)x^2 + (36 - 10 + 15)x - 60#
#y = -1x^2 + 41x - 60#
#y = -x^2 + 41x - 60#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

To find the standard form, expand and simplify the expression: (y = (3x - 5)(2x + 12) - 7x^2 + 15x) Expand: (y = 6x^2 + 36x - 10x - 60 - 7x^2 + 15x) Combine like terms: (y = -x^2 + 41x - 60) The standard form of the equation is (y = -x^2 + 41x - 60).

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 3

The standard form of ( y = (3x - 5)(2x + 12) - 7x^2 + 15x ) is ( y = -7x^2 + 15x + 36x - 60 - 7x^2 + 15x ), which simplifies to ( y = -14x^2 + 66x - 60 ).

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7