What is the standard form of #y= (3x-1)(4x-2) #?

Answer 1

#y=12x^2-10x+2#

The general standard form for a quadratic is: #color(white)("XXX")y=ax^2+bx+c#

The given equation: #y=(color(red)(3x-1))(color(blue)(4x-2))# can be transformed into the standard form by multiplying the factors on the right side.

#{: (xx," |",color(red)(3x),color(red)(-1)), ("-----",,"-----","-----"), (color(blue)(4x)," |",12x^2,-4x), (color(blue)(-2)," |",-6x,+2), ("-----","-----","-----","-----"), (,color(green)(12x^2),color(green)(-10x),color(green)(+2)) :}#

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Answer 2

Eva Adamson

The standard form of the expression ( y = (3x - 1)(4x - 2) ) is ( y = 12x^2 - 10x + 2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.