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What is the standard form of #y= (3/5x^2-1/2)(1/6x+7/8) #?

Answer 1

#y=1/10x^3+21/40x^2-1/12x-7/16#

Distribute using the FOIL method.

#y=overbrace(3/5x^2(1/6x))^("first")+overbrace(3/5x^2(7/8))^("outside")+overbrace(-1/2(1/6x))^("inside")+overbrace(-1/2(7/8))^("last")#

Multiply the fractions.

#y=1/10x^3+21/40x^2-1/12x-7/16#

This is in standard form since the degree of the each term is lower than the previous .

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Answer 2

Ethan Adkins

The standard form of the given equation is y = (9/30)x^3 + (21/80)x^2 - (1/12)x - (7/16)x + (49/160).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.