What is the standard form of # f=(x - 2)(x - 2)(x + y)(x - y) #?

Answer 1
To find the standard form of #f#, we need to first expand the brackets and rearrange them in a descending power of degree.
#f=(x-2)(x-2)(x+y)(x-y)# #=(x-2)^2* (x+y)(x-y)#

we can use identities to expand it. Identities :

#(a-b)^2=a^2-2ab+b^2#
#(a+b)(a-b)=a^2-b^2#
#f=(x^2-2(x)(2)+2^2)(x^2-y^2)# #=(x^2-4x+4)(x^2-y^2)# #=(x^2)(x^2-y^2)-4x(x^2-y^2)+4(x^2-y^2)# #=x^4-x^2y^2-4x^3+4xy^2+4x^2-4y^2#
Remarks: #x^2y^2# have a degree of #4#, where #2# from #x^2# and #2# from #y^2#

As it is already in a descending degree of power, we don't have to rearrange it and it's the answer. Hope this can help you.

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Answer 2

The standard form of ( f = (x - 2)(x - 2)(x + y)(x - y) ) is ( f = (x - 2)^2(x + y)(x - y) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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