What is the speed of an object that travels from #( -5 , 2, 3 ) # to #(6 , 0, 7 ) # over #4 s#?

Answer 1

#v~=2,97m/s#

#"Distance between two point is equal to :"# #s=sqrt (Delta x^2+Delta y^2+Delta z^2)# #s=sqrt(11²+(-2)^2+4^2)# #s=sqrt (121+4+16)# #s=sqrt 141=11,87m# #v=s/t# #v=(11,87)/4# #v~=2,97m/s#

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Answer 2

Adam Arnold

To find the speed of an object traveling from one point to another, you calculate the distance between the two points and then divide it by the time taken. Using the distance formula, d = sqrt((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2) d = sqrt((6 - (-5))^2 + (0 - 2)^2 + (7 - 3)^2) d = sqrt(11^2 + (-2)^2 + 4^2) d = sqrt(121 + 4 + 16) d = sqrt(141) d ≈ 11.87 Speed = distance / time = 11.87 m / 4 s = 2.97 m/s.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.