# What is the speed of an object that travels from #( -4,6,1) # to #( -1,4,-2 ) # over #2 s#?

2,35 m/s

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To find the speed of the object, calculate the distance traveled using the formula for distance between two points in three-dimensional space: Distance = √((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2) Then divide the distance by the time taken: Speed = Distance / Time Using the coordinates provided: Distance = √((-1 - (-4))^2 + (4 - 6)^2 + (-2 - 1)^2) Distance = √(3^2 + (-2)^2 + (-3)^2) Distance = √(9 + 4 + 9) Distance = √22 ≈ 4.69 units Speed = 4.69 units / 2 s ≈ 2.35 units/s

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- An object is thrown vertically from a height of #9 m# at # 2 m/s#. How long will it take for the object to hit the ground?
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