What is the specific heat capacity of silver metal if 55.00 g of the metal absorbs 47.3 calories of heat and the temperature rises 15.0°C?

Answer 1

See below.

The equation used to solve for specific heat capacity is this:

#q=s*m*DeltaT# where q heat absorbed or lost, s is the specific heat capacity, m is the mass, and #DeltaT# is the change in temperature #"final temperature"-"initial temperature"#

From what the problem gave us, we can plug in the numbers:

#47.3=s*55.00*15.0#

Simplify:

#47.3=s*825#

Divide by 825 on both sides:

#0.0573=s#

The units of #s# will be in #"cal"/(g*C# for this problem, so #s=0.0573 "cal"/(g*C)#

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Answer 2

Luna Chen

The specific heat capacity of silver metal is ( 0.056 \frac{cal}{g°C} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.