What is the solubility product of calcium hydroxide?

Answer 1
The Ksp for calcium hydroxide is Ksp = #[Ca^(2+)][OH^-]^2#

To solve this, you must apply the law of mass action and the dissociation equation.

#CaOH_2#(s) -> #Ca^(2+)# + 2#OH^-#
Solid substances are not included in writing an equilibrium expression. So you will only have the #Ca^(2+)# and the #OH^-# in the expression. The calcium ion has no exponent, the hydroxide ion must be squared because of the coefficient of 2.
The Ksp value for 4.68×10-6 for #CaOH_2# indicates that this is a moderately soluble compound.
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Answer 2

The solubility product (Ksp) of calcium hydroxide (Ca(OH)2) is approximately (5.5 \times 10^{-6}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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