What is the slope of the tangent line of #x^3y^2-(x+y)/(x-y)^2= C #, where C is an arbitrary constant, at #(1,4)#?

Answer 1

Slope of tangent line is #-1303/203#

As we are seeking slope at #(1,4)#, this point lies on the curve given by #x^3y^2-(x+y)/(x-y)^2=C#.
Putting values from #(1,4)#, we get #1^3*4^2-(1+4)/(1-4)^2=C#
or #C=16-5/9=139/9# and function is #x^3y^2-(x+y)/(x-y)^2=139/9#
Now differentiating the imlicit function #x^3y^2-(x+y)/(x-y)^2=C#
#3x^2y^2+2x^3y(dy)/(dx)-(1+(dy)/(dx))/(x-y)^2-(2(x+y))/(x-y)^3(1-(dy)/(dx))=0#
or #3x^2y^2(x-y)^3+2x^3y(x-y)^3(dy)/(dx)-(x-y)(1+(dy)/(dx))-2(x+y)(1-(dy)/(dx))=0#
or #[2x^3y(x-y)^3-(x-y)+2(x+y)] (dy)/(dx)=[-3x^2y^2(x-y)^3+x-y+2(x+y)]#
or #(dy)/(dx)=[-3x^2y^2(x-y)^3+x-y+2(x+y)]/[2x^3y(x-y)^3-(x-y)+2(x+y)]#
= #[-3x^2y^2(x-y)^3+3x+y]/[2x^3y(x-y)^3+x+3y]#
and at #(1,4)#, slope is #[-3*1^2*4^2(1-4)^3+3+4]/[2*1^3*4(1-4)^3+1+3*4]#
= #(48*27+7)/(-8*27+13)#
= #-1303/203#
The tangent at #(1,4)# looks liike:

graph{(x^3y^2-(x+y)/(x-y)^2-139/9)(203y-812+1303x-1303)=0 [-10.87, 9.13, -4.08, 5.92]}

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Answer 2

To find the slope of the tangent line at the point (1,4), you need to differentiate the given equation implicitly with respect to x, then substitute the values of x and y at the point (1,4), and solve for the derivative dy/dx. After that, evaluate dy/dx at the point (1,4) to get the slope of the tangent line. The result is the slope of the tangent line at the point (1,4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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