# What is the slope of the tangent line of #(1-x)(3-4y^2)-lny = C #, where C is an arbitrary constant, at #(1,1)#?

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To find the slope of the tangent line at the point (1,1) for the curve (1-x)(3-4y^2) - ln(y) = C:

- Differentiate implicitly with respect to x.
- Find the derivative of each term using the product rule and the chain rule.
- Plug in the coordinates (1,1) to find the slope of the tangent line.

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