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What is the slope of the line that contains the points (-1, -1) and (3, 15)?

Answer 1

Savannah Anderson

#m=4#

The slope-finding equation is

#m=(y_2-y_1)/(x_2-x_1)#.

It does not matter which coordinate is used as #1# or #2# as long as there is consistency.

Now let's enter the coordinates into the formula:

#m=(-1-15)/(-1-3)#

#m=(-16)/-4#

#m=4#

I hope this is useful.

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Answer 2

Eli Assouline

To find the slope of the line passing through two points, you can use the formula:

Slope = (y2 - y1) / (x2 - x1)

Substitute the coordinates of the given points into the formula:

Slope = (15 - (-1)) / (3 - (-1))

Slope = (15 + 1) / (3 + 1)

Slope = 16 / 4

Slope = 4

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Answer 3

Abigail Allen

To find the slope of the line that contains the points (-1, -1) and (3, 15), you can use the formula for slope, which is given by:

[ m = \frac{y_2 - y_1}{x_2 - x_1} ]

where ((x_1, y_1)) and ((x_2, y_2)) are the coordinates of the two points.

Substitute the given coordinates into the formula:

[ m = \frac{15 - (-1)}{3 - (-1)} ]

[ m = \frac{15 + 1}{3 + 1} ]

[ m = \frac{16}{4} ]

[ m = 4 ]

Therefore, the slope of the line that contains the points (-1, -1) and (3, 15) is (4).

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Answer from HIX Tutor

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