What is the slope of the line normal to the tangent line of #f(x) = x^3-sqrtx # at # x= 3 #?
The slope of tangent can be found by taking the first derivative. The slope of the normal is the negative reciprocal of the slope of the tangent.
The slope of normal would be the negative reciprocal of this value.
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The slope of the line normal to the tangent line of f(x) = x^3 - sqrt(x) at x = 3 is -1/18.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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