# What is the slope of the line normal to the tangent line of #f(x) = secx+cos^2(2x-pi) # at # x= (11pi)/8 #?

Find the function derivative

Evalute the derivative

This (complicated) value is the slope of the tangent line at the given point.

Calculate the normal slope

so

By signing up, you agree to our Terms of Service and Privacy Policy

To find the slope of the line normal to the tangent line of (f(x) = \sec(x) + \cos^2(2x - \pi)) at (x = \frac{11\pi}{8}), first find the derivative of the function, then evaluate it at the given (x)-value to find the slope of the tangent line. Then, take the negative reciprocal of this slope to find the slope of the line normal to the tangent line.

By signing up, you agree to our Terms of Service and Privacy Policy

- What is the equation of the tangent line of #y=(x-1)^3# at #x=2#?
- How to find instantaneous rate of change for #f(x)=4 ·x^2+4 ·x−3# when x=4?
- How do you find f'(x) using the definition of a derivative for #f(x)= x^2 + x#?
- How do you find the derivative of # f(x) = sqrtx# using the formal definition?
- What is the equation of the line tangent to #f(x)=y=e^x sin^2x# at #x=sqrtpi#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7