What is the slope of the line normal to the tangent line of #f(x) = cosx*sin(2x-pi/6) # at # x= pi/3 #?
Let's first find the derivative of the function using the product rule :
So now the slope of the normal line to the tangent is :
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The slope of the line normal to the tangent line of ( f(x) = \cos(x) \cdot \sin(2x-\frac{\pi}{6}) ) at ( x = \frac{\pi}{3} ) is -1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- What is the equation of the tangent line of #f(x)=ln(3x)^2-x^2# at #x=3#?
- What is the equation of the line normal to #f(x)=(x+1)^2# at #x=-1#?

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