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What is the slope of any line perpendicular to the line passing through #(44,15)# and #(-5,-3)#?

Answer 1

Eva Adamson

The requested slope is #-49/18#

The slope of the line passing through (44,15) and (-5,-3) is given by:

#m=(y_2-y_1)/(x_2-x_1)=(-3-15)/(-5-44)=(-18)/-49=18/49#

The slope of a line perpendicular to this one is obtained by:

#m'=-1/m=-49/18#

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Answer 2

Ethan Adkins

To find the slope of the line passing through the points (44, 15) and (-5, -3), we use the formula:

slope = (y2 - y1) / (x2 - x1)

Substituting the coordinates into the formula:

slope = (-3 - 15) / (-5 - 44) = (-3 - 15) / (-5 - 44) = (-18) / (-49) = 18/49

To find the slope of a line perpendicular to this line, we take the negative reciprocal of the slope:

perpendicular_slope = -1 / slope = -1 / (18/49) = -49/18

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Answer from HIX Tutor

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