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What is the slope of any line perpendicular to the line passing through #(-24,19)# and #(-8,15)#?

Answer 1

Genesis Allen

Slope of desired line is #4#.

Slope of a line joining #(x_1,y_1)# and #(x_2,y_2)# is given by

#(y_2-y_1)/(x_2-x_1)#

Hence, slope the line passing through (−24,19) and (−8,15) is #(15-19)/(-8-(-24))=-4/16=-1/4#.

As product of slopes two perpendicular lines is #-1#, slope of desired line will be #(-1)/(-1/4)=-1xx-4=4#.

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Answer 2

Eva Abramson

Slope of desired line is #4#.

Slope of a line joining #(x_1,y_1)# and #(x_2,y_2)# is given by

#(y_2-y_1)/(x_2-x_1)#

Hence, slope the line passing through (−24,19) and (−8,15) is #(15-19)/(-8-(-24))=-4/16=-1/4#.

As product of slopes two perpendicular lines is #-1#, slope of desired line will be #(-1)/(-1/4)=-1xx-4=4#.

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Answer 3

Isaiah Anthony

To find the slope of the line passing through (-24, 19) and (-8, 15), use the formula: slope = (y2 - y1) / (x2 - x1).

So, the slope is (15 - 19) / (-8 - (-24)), which simplifies to -4 / 16, which further simplifies to -1/4.

The slope of any line perpendicular to this line would be the negative reciprocal of -1/4, which is 4. Therefore, the slope of any line perpendicular to the line passing through (-24,19) and (-8,15) is 4.

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Answer from HIX Tutor

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