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What is the slope of any line perpendicular to the line passing through #(12,-5)# and #(-1,7)#?

Answer 1

Isaiah Anthony

Slope of the perpendicular to the line joining #(12,-5)# and #(-1,7)# is #13/12#

Slope of a line joining #(x_1,y_1)# and #(x_2,y_2)# is

#(y_2-y_1)/(x_2-x_1)#

Therefore slope of line joining #(12,-5)# and #(-1,7)# is

#(7-(-5))/(-1-12)=12/(-13)=-12/13#

As product of slopes of two lines perpendicular to each other is #-1#

slope of the perpendicular to the line joining #(12,-5)# and #(-1,7)# is

#(-1)/(-12/13)=(-1)xx(-13/12)=13/12#

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Answer 2

Ethan Adkins

To find the slope of the line passing through (12, -5) and (-1, 7), first, calculate the slope using the formula:

m = (y2 - y1) / (x2 - x1)

Then, find the negative reciprocal of this slope to get the slope of any line perpendicular to it.

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Answer from HIX Tutor

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