What is the slope of any line perpendicular to the line passing through #(0,2)# and #(3,15)#?

Answer 1

The slope of any line passing through the given two points is #-3/13#.

Determine the line's slope that passes through the two provided points first.

#m=(y_2-y_1)/(x_2-x_1)#,

where:

#m# is the slope, and #(x_1,y_1)# and #(x_2,y_2)# are the two given points. I'm going to use point #(0,2)# as #(x_1,y_1)# and #(3,15)# as #(x_2,y_2)#. You could do the reverse and you would get the same slope.

Slope can be calculated by plugging in the known values.

#m=(15-2)/(3-0)#
#m=13/3#
The perpendicular slope of any line is the negative reciprocal of the original slope, so that #m_1m_2=-1#.
#13/3xx-3/13=-39/39=-1#. The perpendicular slope is #-3/13#.

graph{[-10, 10, -5, 5]} = (y+13/3x)(y-3/13x)=0

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Answer 2

The slope of any line perpendicular to the line passing through (0,2) and (3,15) is -3/13.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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