What is the slope of a line perpendicular to the graph of the equation 5x - 3y =2?
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The slope of a line perpendicular to the graph of the given equation is
Given:
This is a linear equation in standard form. To determine the slope, convert the equation into slope-intercept form:
graph{(5x-3y-2)(y+3/5x)=0 [-10, 10, -5, 5]}
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To find the slope of a line perpendicular to the graph of the equation (5x - 3y = 2), first solve for (y) to put it in slope-intercept form (y = mx + b). Then, identify the slope of the original line as (m). The slope of a line perpendicular to it will be the negative reciprocal of (m).
Given the equation (5x - 3y = 2), rearrange it to solve for (y): [ 5x - 3y = 2 ] [ -3y = -5x + 2 ] [ y = \frac{5}{3}x - \frac{2}{3} ]
The slope of the original line is (m = \frac{5}{3}). The slope of a line perpendicular to it is the negative reciprocal of (m), which is (-\frac{3}{5}). Therefore, the slope of a line perpendicular to the graph of (5x - 3y = 2) is (-\frac{3}{5}).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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