What is the slope-intercept form of the line passing through #(6, 1) # and # (4, 5) #?

Answer 1

#y=-2x+13#

Slope-intercept form: y=mx+b, where m is the slope and b is the y-intercept

Finding the slope using 2 points:

#(y_2-y_1)/(x_2-x_1) rarr# Divide the difference of the y coordinates by the difference of the x coordinates
#(5-1)/(4-6)#
#4/-2#
#-2 rarr# This is the slope.
Our equation is currently #y=-2x+b#

To find b, let's plug in one of the coordinates.

#1=-2*6+b#
#1=-12+b#
#b=13#
Our equation is: #y=-2x+13#
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Answer 2

The slope-intercept form of the line passing through (6, 1) and (4, 5) is y = -2x + 13.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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