What is the slope intercept form of the line passing through #(4,-8) # with a slope of #5/4 #?

Answer 1
So we know that the slope is #5/4#
We can plug that into the equation #y = mx+b# because the m represents the slope
So now we have #y = 5/4x + b#

We also know one coordinate, and that is all that we need.

Plug that coordinate into the equation and we are now solving for one variable, #b#
So, we have #-8 = 5/4(4)+b# by plugging in the coordinate pair
Then we have #-8 = 5+b# Move the #5# over and we have #b = -13#
Thus, our equation is #y = 5/4x - 13#

And we are done.

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Answer 2

The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.

Given the slope (m = 5/4) and a point (4, -8), we can use the point-slope form to find the equation.

Substituting the values into the point-slope form: y - y₁ = m(x - x₁), y - (-8) = (5/4)(x - 4), y + 8 = (5/4)x - 5, y = (5/4)x - 13.

So, the slope-intercept form of the line passing through (4, -8) with a slope of 5/4 is y = (5/4)x - 13.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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